Listed below are the top 10 annual salaries​ (in millions of​ dollars) of TV personalities. Find the​ range, variance, and standard deviatio

Question

Listed below are the top 10 annual salaries​ (in millions of​ dollars) of TV personalities. Find the​ range, variance, and standard deviation for the sample data. Given that these are the top 10​ salaries, do we know anything about the variation of salaries of TV personalities in​ general? 41 39 38 31 21 20 18 16 15.7 15.2

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Alice 3 weeks 2021-09-26T01:09:26+00:00 1 Answer 0

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    2021-09-26T01:10:41+00:00

    Answer:

    a) Range = 25.8 million

    Variance = 1008.129

    Standard deviation = 10.04 million

    b) No, we do not know anythjng about the variation of salaries of TV personalities in general as the behaviour of the entire data set cannot be determined just by examining the topmost values. For all we know, these could be the most outlier numbers.

    Step-by-step explanation:

    The top 10 annual salaries (in million of dollars) of TV personalities

    41 39 38 31 21 20 18 16 15.7 15.2

    Range = Difference between the highest value and the lowest value.

    For this set of data,

    Range = 41 – 15.2 = 25.8 million.

    Variance is an average of the squared deviations from the mean.

    It is given mathematically as

    Variance = [Σ(x – xbar)²/N]

    where x = each variable

    xbar = mean of the data set

    N = number of variables = 10

    First of, we find the mean,

    The mean, xbar, is the sum of variables divided by the number of variables.

    xbar = (Σx)/N = (41 + 39 + 38 + 31 + 21 + 20 + 18 + 16 + 15.7 + 15.2)/10 = (254.9/10)

    xbar = 25.49

    Σ(x – xbar)² = (41 – 25.49)² + (39 – 25.49)² + (38 – 25.49)² + (31 – 25.49)² + (21 – 25.49)² + (20 – 25.49)² + (18 – 25.49)² + (16 – 25.49)² + (15.7 – 25.49)² + (15.2 – 25.49)² = 1008.129

    Variance = [Σ(x – xbar)²/N] = (1008.129/10)

    Variance = 100.8129

    Standard deviation = √(variance) = √(100.8129) = 10.04 million

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45:7+7-4:2-5:5*4+35:2 =? ( )