Mrs. Braddock has a bag containing 6 lipsticks, 4 eye shadows, 6 eye liners, and 5 mascaras. She will randomly choose one item from the bag.

Question

Mrs. Braddock has a bag containing 6 lipsticks, 4 eye shadows, 6 eye liners, and 5 mascaras. She will randomly choose one item from the bag.What is the probability that she will pull NOT lipstick? p(NOT lipstick). Round percents to nearest whole number

in progress 0
Kinsley 1 month 2021-10-12T04:53:11+00:00 1 Answer 0 views 0

Answers ( )

  1. Ava
    0
    2021-10-12T04:54:46+00:00

    Answer:

    The probability that she will not pull lipstick is 71%.

    Step-by-step explanation:

    The probability of an event E is the ratio of the favorable number of outcomes to the total number of outcomes.

    P(E)=\frac{n(E)}{N}

    Here,

    n (E) = favorable number of outcomes

    N = total number of outcomes

    The contents in Mrs. Braddock’s bag are:

    Number of lipsticks = n (L) = 6

    Number of eye shadows = n (S) = 4

    Number of eye liners = n (E) = 6

    Number of mascaras = n (M) = 5

    Total number of items in the bag = N = 21

    Consider that the probability of an event occurring is P. Then the probability of the given event not taking place is known as the complement of that event.

    Complement of the given event is, 1 – P.

    Compute the probability of selecting a lipstick as follows:

    P(L)=\frac{n(L)}{N}\\\\=\frac{6}{21}\\\\=\frac{2}{7}

    Compute the  probability of not selecting a lipstick as follows:

    P(L^{c})=1-P(L)

              =1-\frac{2}{7}\\\\=\frac{7-2}{7}\\\\=\frac{5}{7}

    Convert this probability into percentage as follows:

    \frac{5}{7}\times 100 = 71.4286\approx 71\%

    Thus, the probability that she will not pull lipstick is 71%.

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )