Mrs lin is sewing costumes for her grandchildren.She is making three lion costumes one zebra costume and two bear. Costumes fabric costs $ 7

Question

Mrs lin is sewing costumes for her grandchildren.She is making three lion costumes one zebra costume and two bear. Costumes fabric costs $ 7.49 per yard how much fabric does Mrs lin need

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Adalyn 18 mins 2022-01-03T04:48:38+00:00 1 Answer 0 views 0

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    2022-01-03T04:49:41+00:00

    Answer: 12.123\ yards

    Step-by-step explanation:

    The complete exercise is: “Mrs. Lin is sewing costumes for her grandchildren. She is making three lion costumes, one zebra costume, and two bear costumes. Fabric costs $7.49 per yard. How much fabric does Mrs. Lin need?

    Bear= 2 \frac{1}{4}\ yards \\\\Lion= 1 \frac{2}{3}\ yards\\\\Zebra= 2 \frac{5}{8} yards

    You need to find the total amount of fabric (in yards) that Mrs. Lin needs to make three lion costumes, one zebra costume, and two bear costumes.

    Let be:

    • ¬†“l” the amount of fabric (in yards) that Mrs. Lin needs to make ¬†three lion costumes.
    • “z” the amount of fabric (in yards) that Mrs. Lin needs to make one zebra costume.
    • “b” the amount of fabric (in yards) that Mrs. Lin needs to make two bear costumes.

    First, you can convert the mixed numbers given in the exercise to decimal numbers:

    – Divide the numerator by the denominator.

    – Add the quotient to the Whole number part.

    Then:

    Bear= (2+0.25)\ yards=2.25\ yards \\\\Lion=(1+0.666)\ yards=1.666\ yards\\\\Zebra=(2+0.625)=2.625\ yards

    Therefore, you can determine that “l”, “z” and “b” are:

    l=3(1.666\ yards)=4.998\ yards\\\\z=2.625\ yards\\\\b=2(2.25\ yards)=4.5\ yards

    Finally, in order to find the total amount of frabric (in yards) that she needs, you need to add “l”, “z” and “b”. Then, you get:

    Total=l+z+b\\\\Total=4.998\ yards+2.625\ yards+4.5\ yards\\\\Total=12.123\ yards

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