My Notes A spring has a natural length of 22 cm. If a 29-N force is required to keep it stretched to a length of 30 cm, how much work W is r

Question

My Notes A spring has a natural length of 22 cm. If a 29-N force is required to keep it stretched to a length of 30 cm, how much work W is required to stretch it from 22 cm to 26 cm

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Everleigh 2 weeks 2021-09-28T20:08:33+00:00 1 Answer 0

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    2021-09-28T20:10:08+00:00

    Answer:

    W = 0.058 J

    Step-by-step explanation:

    given data

    natural length = 22 cm

    force = 29 N

    length = 30 cm

    stretch = 22 cm to 26 cm

    solution

    force F = K x  …………………1

    K is spring constant and x is length

    Δx = 30 – 26

    Δx = 4 cm = 0.4 m

    and

    F = Kx   …………..2

    29 = K(0.4)

    K = \frac{29}{0.4}

    K = 72.5

    so here

    required work to stretch spring

    W = 0.5 × K  × Δx²   ……………….3

    but here

    Δx = 26-22 = 4 m = 0.04

    and

    W = 0.5 × 72.5  × 0.04²

    W = 0.058 J

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