My Scando-Germanic friend, Odd Zahlen, often brings a die to class to answer multiple-choice final exam questions. Each multiple-choice ques

Question

My Scando-Germanic friend, Odd Zahlen, often brings a die to class to answer multiple-choice final exam questions. Each multiple-choice question on this particular examination consists of three choices, and Odd decides to pick answer (a) if a 1 or 2 appears on a roll of the die, to pick (b) if a 3 or 4 appears on the die, or to pick (c) if a 5 or 6 appears. Assume that the correct answers are uniformly distributed among the choices (a), (b), and (c). What is the probability of obtaining exactly 5 correct answers on a ten question examination using this method?

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Jasmine 2 weeks 2022-01-06T06:02:39+00:00 1 Answer 0 views 0

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    2022-01-06T06:04:05+00:00

    Answer:

    P(A=5)= 0.1366

    Step-by-step explanation:

    From each multiple-choice question, there consists three answers to each;

    So the probability of picking, the correct answer as they are uniformly distributed among the choices (a), (b), and (c) will be;

    P(correct answer) = \frac{1}{3}

    Now, to determine the probability of obtaining exactly 5 correct answers on a ten question examination using this method

    Let use A as representative for the numbers of correct answers out of 10 questions that is being answered.

    P(A=5)= [\left \ {{10} \atop {5}} \right.] (\frac{1}{3}) ^5 (1-\frac{1}{3})^{10-5}

    P(A=5)= [\left \ {{10} \atop {5}} \right.](\frac{1}{3}) ^5 (\frac{2}{3}) ^5

    P(A=5)= 0.13657

    P(A=5)= 0.1366

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45:7+7-4:2-5:5*4+35:2 =? ( )