## Out of the students in a class, 60% are geniuses, 70% love chocolate, and 40% fall into both categories. Determine the probability that a ra

Question

Out of the students in a class, 60% are geniuses, 70% love chocolate, and 40% fall into both categories. Determine the probability that a randomly selected student is neither a genius nor a chocolate lover.

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Math
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2022-02-10T06:46:56+00:00
2022-02-10T06:46:56+00:00 1 Answer
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## Answers ( )

Answer:

0.1

Step-by-step explanation:

Let G represent geniuses

Let C represent chocolate

P(G) = 60% = 0.60

P(C) = 70% = 0.70

P(G and C) = 40% = 0.40

P(G and C) = P(G) + P(C) – P(G or C)

0.4 = 0.6 + 0.7 – P(G or C)

0.4 = 1.3 – P(G or C)

P(G or C) = 1.3 – 0.4

= 0.9

P(student is neither a genius or chocolate lover ) = 1 – P(G or C)

= 1 – 0.9

= 0.1