PLS DO THIS AS QUICK AS POSSIBLE a)2.15a+0.03∙(3.4a−12a) b)3.27x+1.28y+1.83x−2.77y 1)22.5x−4.6=3.5 2)y÷2.3+5.6

Question

PLS DO THIS AS QUICK AS POSSIBLE
a)2.15a+0.03∙(3.4a−12a)
b)3.27x+1.28y+1.83x−2.77y

1)22.5x−4.6=3.5
2)y÷2.3+5.69=7.58

WORD PROBLEM: Car A went 60 km in 5/6 hours while car B went 54 km in 2/3 hours. Which car was faster? How many times faster?
Car __ went faster by __ times

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1 week 2021-10-07T14:44:13+00:00 1 Answer 0

Answers ( )

    0
    2021-10-07T14:45:45+00:00

    Answer:

    a) 1.892a

    b.) 5.1x – 1.49y

    1.) X = 0.36

    2.) Y = 4.347

    Car B went faster by 1.25 times

    Step-by-step explanation:

    a)2.15a+0.03∙(3.4a−12a)

    Open the bracket

    2.15a + 0.102a – 0.36a

    2.252a – 0.36a

    1.892a

    b)3.27x+1.28y+1.83x−2.77y

    Rearranged the algebraic expression above

    3.27x + 1.83x + 1.28y – 2.77y

    5.1x – 1.49y

    1)22.5x−4.6=3.5

    Collect the like term

    22.5x = 8.1

    X = 0.36

    2)y÷2.3+5.69=7.58

    Y/2.3 = 7.58 – 5.69

    Y = 2.3 × 1.89

    Y = 4.347

    WORD PROBLEM: Car A went 60 km in 5/6 hours while car B went 54 km in 2/3 hours.

    Which car was faster?

    That’s speed

    Speed = distance/time

    Speed A = 60 ÷ 5/6 = 72 km/h

    Speed B = 54 ÷ 2/3 = 81 km/h

    How many times faster? 

    5/6 ÷2/3

    5/6 × 3/2

    15/12

    1.25 seconds faster

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45:7+7-4:2-5:5*4+35:2 =? ( )