## PLS DO THIS AS QUICK AS POSSIBLE a)2.15a+0.03∙(3.4a−12a) b)3.27x+1.28y+1.83x−2.77y 1)22.5x−4.6=3.5 2)y÷2.3+5.6

Question

PLS DO THIS AS QUICK AS POSSIBLE
a)2.15a+0.03∙(3.4a−12a)
b)3.27x+1.28y+1.83x−2.77y

1)22.5x−4.6=3.5
2)y÷2.3+5.69=7.58

WORD PROBLEM: Car A went 60 km in 5/6 hours while car B went 54 km in 2/3 hours. Which car was faster? How many times faster?
Car __ went faster by __ times

in progress 0
1 week 2021-10-07T14:44:13+00:00 1 Answer 0

a) 1.892a

b.) 5.1x – 1.49y

1.) X = 0.36

2.) Y = 4.347

Car B went faster by 1.25 times

Step-by-step explanation:

a)2.15a+0.03∙(3.4a−12a)

Open the bracket

2.15a + 0.102a – 0.36a

2.252a – 0.36a

1.892a

b)3.27x+1.28y+1.83x−2.77y

Rearranged the algebraic expression above

3.27x + 1.83x + 1.28y – 2.77y

5.1x – 1.49y

1)22.5x−4.6=3.5

Collect the like term

22.5x = 8.1

X = 0.36

2)y÷2.3+5.69=7.58

Y/2.3 = 7.58 – 5.69

Y = 2.3 × 1.89

Y = 4.347

WORD PROBLEM: Car A went 60 km in 5/6 hours while car B went 54 km in 2/3 hours.

Which car was faster?

That’s speed

Speed = distance/time

Speed A = 60 ÷ 5/6 = 72 km/h

Speed B = 54 ÷ 2/3 = 81 km/h

How many times faster?

5/6 ÷2/3

5/6 × 3/2

15/12

1.25 seconds faster