## Point C is located at (1, 2), and point D is located at (−4, −2). Find the x value for the point that is 1 over 4 the distance from point C

Question

Point C is located at (1, 2), and point D is located at (−4, −2). Find the x value for the point that is 1 over 4 the distance from point C to point D. −0.25 −1.5 −2.75 −4

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1 week 2021-09-11T23:36:28+00:00 2 Answers 0

It’s -0.25

Step-by-step explanation:

If you graph it, you can see it.

Point C is (1,2)

Point D is (-4,-2)

(-0.25, 1) is 1/4 of the distance from point C to point D

Point C occurs on the line x = 1

Point D occurs on the line y = -2

The intersection of both lines occurs at the point E = (1,-2)

The difference between the x coordinates of points D and E is 1 + 1/4 units

The difference between the y coordinates of points C and E is 1 unit

Let point F be the point that is 1/4 the distance from point C to point D

To find the x-coordinate F subtract the difference between the x coordinate of points C and E from the x-coordinate of C:

1 – (1 + 1/4) = -1/4

To find the y-coordinate of F subtract the difference between the y-coordinates of D and E from the y-coordinate of C

2 – 1 = 1

The coordinates of point F are (-1/4, 1)

Therefore, the y value of the point that is 1/4th the