Point C is located at (1, 2), and point D is located at (−4, −2). Find the x value for the point that is 1 over 4 the distance from point C

Question

Point C is located at (1, 2), and point D is located at (−4, −2). Find the x value for the point that is 1 over 4 the distance from point C to point D. −0.25 −1.5 −2.75 −4

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Eva 1 week 2021-09-11T23:36:28+00:00 2 Answers 0

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    0
    2021-09-11T23:37:50+00:00

    Answer:

    It’s -0.25

    Step-by-step explanation:

    If you graph it, you can see it.

    Point C is (1,2)

    Point D is (-4,-2)

    (-0.25, 1) is 1/4 of the distance from point C to point D

    0
    2021-09-11T23:38:04+00:00

    Answer:

    Point C occurs on the line x = 1

    Point D occurs on the line y = -2

    The intersection of both lines occurs at the point E = (1,-2)

    The difference between the x coordinates of points D and E is 1 + 1/4 units

    The difference between the y coordinates of points C and E is 1 unit

    Let point F be the point that is 1/4 the distance from point C to point D

    To find the x-coordinate F subtract the difference between the x coordinate of points C and E from the x-coordinate of C:

    1 – (1 + 1/4) = -1/4

    To find the y-coordinate of F subtract the difference between the y-coordinates of D and E from the y-coordinate of C

    2 – 1 = 1

    The coordinates of point F are (-1/4, 1)

    Therefore, the y value of the point that is 1/4th the

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45:7+7-4:2-5:5*4+35:2 =? ( )