## Question 1: Which equation shows p(x)=x^6−1 factored completely over the integers? (Hint: You will need to use more than one method to compl

Question

Question 1: Which equation shows p(x)=x^6−1 factored completely over the integers? (Hint: You will need to use more than one method to complete this problem.)

a. p(x)=(x^3+1)(x^3−1)

b. p(x)=(x^2−1)(x^4+x^2+1)

c. p(x)=(x−1)(x^2+x+1)(x+1)(x^2−x+1)

d. p(x)=(x−1)(x+1)(x4+x^2+1)

Question 2: Which expression is the expanded form of p(x)=4(x−7)(2x^2+3)?

a. 32x^3−224x^2+48x−336

b. −48x^2+12x−84

c. 8x^3−56x^2+12x−84

d. 8x^3+56x^2−12x−84

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Math
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2021-09-10T14:48:46+00:00
2021-09-10T14:48:46+00:00 1 Answer
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## Answers ( )

Answer:Question #1: Option C, (x – 1)(x^2 + x + 1)(x + 1)(x^2 – x + 1)

Question #2: Option C, 8x^3−56x^2+12x−84

Step-by-step explanation:Question #1Step 1: Factorp(x) = x^6 – 1

p(x) = (x + 1)(x – 1)(x^2 + x + 1)(x^2 – x + 1)Answer:

Option C, (x – 1)(x^2 + x + 1)(x + 1)(x^2 – x + 1)Question #2Step 1: Expandp(x) = 4(x – 7)(2x^2 + 3)

p(x) = (4x – 28)(2x^2 + 3)

p(x) = 8x^3 + 12x – 56x^2 – 84

p(x) = 8x^3 – 56x^2 + 12x – 84Answer:

Option C, 8x^3−56x^2+12x−84