Renaldo has six times as many oranges as mangoes. He has 49 pieces of fruit in all. Let r represent the number of oranges and m represent th

Question

Renaldo has six times as many oranges as mangoes. He has 49 pieces of fruit in all. Let r represent the number of oranges and m represent the number of mangoes. How many of each fruit does Renaldo have? Use the table to answer the question. 4 mangoes and 45 oranges 7 mangoes and 42 oranges 8 mangoes and 41 oranges 9 mangoes and 40 oranges

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Katherine 3 months 2022-02-12T04:34:56+00:00 2 Answers 0 views 0

Answers ( )

    0
    2022-02-12T04:35:56+00:00

    Answer:

    its B

    Step-by-step explanation:

    0
    2022-02-12T04:36:45+00:00

    Answer:

    He have 42 oranges and 7 mangoes.

    The correct answer is 7 mangoes and 42 oranges.

    Step-by-step explanation:

    Given:

    Renaldo has six times as many oranges as mangoes. He has 49 pieces of fruit in all. Let r represent the number of oranges and m represent the number of mangoes.

    Now to find the number of each fruit Renaldo have.

    As, given:

    Let [tex]r[/tex] represent the number of oranges and [tex]m[/tex] represent the number of mangoes.

    So, as he has six times as many oranges as mangoes.

    Thus,

    [tex]r=6m[/tex]     ……….( 1 )

    Total number of fruits = 49.

    According to question:

    [tex]m+r=49[/tex]

    Substituting the value of [tex]r[/tex] from equation (1) we get:

    [tex]m+6m=49[/tex]

    [tex]7m=49[/tex]

    Dividing both sides by 7 we get:

    [tex]m=7.[/tex]

    Number of mangoes = 7.

    Now, to get the number of oranges we put the value of [tex]m[/tex] in equation (1):

    [tex]r=6m[/tex]

    [tex]r=6\times 7[/tex]

    [tex]r=42.[/tex]

    The number of oranges = 42.

    Therefore, he have 42 oranges and 7 mangoes.

    The correct answer is 7 mangoes and 42 oranges.

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45:7+7-4:2-5:5*4+35:2 =? ( )