Replace ∗ with a monomial so that the derived equality will be an identity: (15y + ∗)^2 = 225y^2+12x^3y+0.16x^6

Question

Replace ∗ with a monomial so that the derived equality will be an identity: (15y + ∗)^2 = 225y^2+12x^3y+0.16x^6

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2 weeks 2021-10-07T17:52:12+00:00 2 Answers 0

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    0
    2021-10-07T17:53:44+00:00

    Answer:

    Step-by-step explanation:

    (a + b)² = a² + 2ab + b²

    a = 15y

    2ab = 12x³y  

    2* 15y*b = 12x³y  

    b=\frac{12*x^{3}*y}{2*15*y}\\\\b=\frac{2x^{3}}{5}\\\\b=0.4x^{3}

    (15y + 0.4x³)

    0
    2021-10-07T17:54:11+00:00

    Answer:

    ∗ = 0.4x³

    Step-by-step

    We have :

    2×(0,4)×15=12

    (0,4)^2=0,16

    (15y + ∗)^2 = 225y² + 12x³y + 0.16x⁶

                     = (15y)² + 2×(15y)×(0.4x³) + (0.4x³)²

    then

    ∗ = 0.4x³

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