Sarah kicked a ball in the air. The function f ff models the height of the ball (in meters) as a function of time (in seconds)

Question

Sarah kicked a ball in the air. The function
f
ff models the height of the ball (in meters) as a function of time (in seconds) after Sarah kicked it.

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Samantha 1 week 2021-09-08T01:31:47+00:00 2 Answers 0

Answers ( )

    0
    2021-09-08T01:32:58+00:00

    Answer: The ball hits the ground at 5 s

    Step-by-step explanation:

    The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:

    f=30 t- 6t^{2} (1)

    Where f models the height of the ball in meters and t the time.

    Now, let’s find the time t when the ball Sara kicked hits the ground (this is when f=0 m):

    0=30 t- 6t^{2} (2)

    Rearranging the equation:

    6t^{2}-30 t=0 (3)

    Dividing both sides of the equation by 6:

    t^{2}-5 t=0 (4)

    This quadratic equation can be written in the form at^{2}+bt+c=0, and can be solved with the following formula:  

    t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} (5)  

    Where:  

    a=1  

    b=-5  

    c=0  

    Substituting the known values:  

    t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(0)}}{2(1)} (6)  

    Solving we have the following result:

    t=5 s  This means the ball hit the ground 5 seconds after it was kicked by Sara.

    0
    2021-09-08T01:33:39+00:00

    Answer: Sarah kicked the ball from a height of about 1\text{ m}1 m1, start text, space, m, end text.

    At its highest point, the ball was about 14\text{ m}14 m14, start text, space, m, end text above the ground.

    Step-by-step explanation:

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45:7+7-4:2-5:5*4+35:2 =? ( )