## Suppose a laboratory has a 26-gram sample of polonium-210.The half-life of polonium-210 is about days. a.How many half-lives of polonium-210

Question

Suppose a laboratory has a 26-gram sample of polonium-210.The half-life of polonium-210 is about days. a.How many half-lives of polonium-210 occur in 276 days? b.How much polonium is left in the sample after 276 days?

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2021-09-25T22:08:46+00:00
2021-09-25T22:08:46+00:00 2 Answers
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## Answers ( )

Answer:a)Two half lives,b)Step-by-step explanation:a)The polonium-210 has a half life of 138.4 days. Therefore, 1.994 half lives have past.b)Mass decay is described by the following exponential model:The time constant for the isotope is:

The mass of the isotope after 276 days is:

Answer:

Step-by-step explanation:

Given:

t1/2 = 138 days

t = 276 days

No = 26 g

t/t1/2 = 276/138

= 2 half-lifes

N(t) = No × (1/2)^(t/t1/2)

= 26 × (1/2)^2

N(276 days) = 6.5 g