sin pi/4sinpi/6 = 1/2[__pi/12-cos5pi/12]

Question

sin pi/4sinpi/6 = 1/2[__pi/12-cos5pi/12]

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Savannah 2 months 2021-10-05T16:06:08+00:00 2 Answers 0 views 0

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    2021-10-05T16:07:26+00:00

    My peanut brain is too small to understand sorry

    0
    2021-10-05T16:07:54+00:00

    Answer:

    Step-by-step explanation:

    2 sin a sin b=cos(a-b)-cos (a+b)

    2 sin \frac{\pi }{4} sin \frac{\pi }{6}=cos (\frac{\pi }{4}-\frac{\pi }{6})-cos (\frac{\pi }{4} +\frac{\pi }{6} )\\=cos (\frac{3 \pi-2 \pi  }{12} )-cos (\frac{3 \pi+2\pi}{12} )\\=cos (\frac{\pi }{12} )-cos(  \frac{5 \pi}{12} )\\sin \frac{ \pi}{4} sin\frac  {\pi}{6}=\frac{1}{2}[cos \frac{\pi}{12} -cos \frac{5 \pi}{12} ]

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45:7+7-4:2-5:5*4+35:2 =? ( )