Solve systems of equations -x^2-4x+y=0 -x^2+9x+y+13=0 Question Solve systems of equations -x^2-4x+y=0 -x^2+9x+y+13=0 in progress 0 Math Serenity 2 weeks 2021-09-14T19:32:32+00:00 2021-09-14T19:32:32+00:00 1 Answer 0

## Answers ( )

Answer:I solve it by substitution

y=x^2+4x

-x^2+9x+(x^2+4x)+13=0

13x+13=0

13x=-13

x= -13/13

x= -1

y=x^2+4x=1-4

y= -3Step-by-step explanation: