Solve systems of equations -x^2-4x+y=0 -x^2+9x+y+13=0

Question

Solve systems of equations

-x^2-4x+y=0
-x^2+9x+y+13=0

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Serenity 2 weeks 2021-09-14T19:32:32+00:00 1 Answer 0

Answers ( )

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    2021-09-14T19:33:58+00:00

    Answer:

    I  solve  it by substitution

    y=x^2+4x

    -x^2+9x+(x^2+4x)+13=0

    13x+13=0

    13x=-13

    x= -13/13

    x= -1

    y=x^2+4x=1-4

    y= -3

    Step-by-step explanation:

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