solve the equation by completing the square. enter the smallest solution first and round to the nearest tenth s^²-8s=4

Question

solve the equation by completing the square. enter the smallest solution first and round to the nearest tenth
s^²-8s=4

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Natalia 4 weeks 2021-12-30T23:50:24+00:00 1 Answer 0 views 0

Answers ( )

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    2021-12-30T23:51:45+00:00

    Answer:

    Step-by-step explanation:

    Step 1, coefficience of X= -8

    Step 2, divide coefficience by 2 =-4

    Step 3, Square the answer= 16

    step 4, Add to both sides of the equation

    s^2-8x+16=4+16

    s^2+16=20

    s^2+4^2=20

    (s+4)^2=20

    take the squre root of both sides

    s+4=sqrt(20)

    s=4+or -sqrt20

    s=4+4.5 or 4-4.5

    s=8.5 or 0.5

    rounding up we have

    s=10 or 1(to the nearest ten0)

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45:7+7-4:2-5:5*4+35:2 =? ( )