Solve the system using substitution. 3x+5y=15 2x+4y=8

Question

Solve the system using substitution.
3x+5y=15 2x+4y=8

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Peyton 2 weeks 2021-09-27T03:11:22+00:00 1 Answer 0

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    2021-09-27T03:12:35+00:00

    Answer:

    x=10

    y=-3

    Step-by-step explanation:

    3x + 5y= 15…eqn. 1

    2x + 4y= 8…eqn. 2

    multiply eqn. 1 by 2 and eqn. 2 by 3

    6x + 10y = 30…eqn. 3

    6x + 12y = 24…eqn. 4

    0 – 2y = 6

    divide both sides by the coefficient of y which is -2

    – 2y = 6

    – 2 -2

    y= -3

    Put y= -3 into eqn. 1

    3x + 5(-3) = 15

    3x – 15 = 15

    3x =15 + 15

    3x = 30

    3 3

    x = 10

    Therefore X= 10 and Y= -3

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