Solve the system using substitution. 3x+5y=15 2x+4y=8 Question Solve the system using substitution. 3x+5y=15 2x+4y=8 in progress 0 Math Peyton 2 weeks 2021-09-27T03:11:22+00:00 2021-09-27T03:11:22+00:00 1 Answer 0

## Answers ( )

Answer:x=10

y=-3

Step-by-step explanation:3x + 5y= 15…eqn. 1

2x + 4y= 8…eqn. 2

multiply eqn. 1 by 2 and eqn. 2 by 3

6x + 10y = 30…eqn. 3

6x+12y=24…eqn. 40 – 2y = 6

divide both sides by the coefficient of y which is -2

– 2y=6– 2 -2

y= -3

Put y= -3 into eqn. 1

3x + 5(-3) = 15

3x – 15 = 15

3x =15 + 15

3x=303 3

x = 10

Therefore X= 10 and Y= -3