## Suppose X is a binomial random variable with n 5 25 and p 5 0.80. a. Find the mean, variance, and standard deviation of X. b. Find the proba

Question

Suppose X is a binomial random variable with n 5 25 and p 5 0.80. a. Find the mean, variance, and standard deviation of X. b. Find the probability X is within one standard deviation of the mean. c. Find the probability X is more than two standard deviations from the mean

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2021-09-13T22:35:51+00:00
2021-09-13T22:35:51+00:00 1 Answer
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## Answers ( )

Answer:(a) The mean, variance and standard deviation of random variable

Xare20,4and2respectively.(b) The probability that X is within one standard deviation of the mean is

0.7926.(c) The probability that X is more than two standard deviations from the mean is

0.0038.Step-by-step explanation:The random variable

follows a Binomial distribution with parameterXn= 25andp= 0.80.The probability mass function of

Xis:The mean, variance and standard deviation of a Binomial distribution is given by:

(

a)Compute the mean, variance and standard deviation of random variable

Xas follows:Thus, the mean, variance and standard deviation of random variable

Xare20,4and2respectively.(

b)Compute the probability that X is within one standard deviation of the mean as follows:

P (μ – σ ≤ X ≤ μ + σ) = P (20 – 2 ≤ X ≤ 20 + 2)

= P (18 ≤ X ≤ 22)

= P (X ≤ 22) – P (X ≤ 18)

= P (X = 18) + P (X = 19) + P (X = 20) + P (X = 21) + P (X = 22)

Thus, the probability that X is within one standard deviation of the mean is

0.7926.(

c)Compute the probability that X is more than two standard deviations from the mean as follows:

P (X > μ + 2σ) = P (X > 20 + (2×2))

= P (X > 24)

= P (X = 25)

Thus, the probability that X is more than two standard deviations from the mean is

0.0038.