Suppose the system of linear equations has no solution. Which is NOT a possible value of the constant for the second equation? 6

Question

Suppose the system of linear equations has no solution. Which is NOT a possible value of the constant for the second equation?

6x + 9y = 15
2x + 3y = __

A) 5
B) 10
C) 15
D) 20

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Abigail 3 hours 2021-10-14T10:17:05+00:00 1 Answer 0

Answers ( )

    0
    2021-10-14T10:18:06+00:00

    Answer:

      A)  5

    Step-by-step explanation:

    The coefficients of the second equation are 1/3 of those of the first equation. If the constant of the second equation is also 1/3 of the constant of the first equation, then the equations are dependent, and will have an infinite number of solutions.

    The constant must be something other than 1/3·15 = 5 to make the equations inconsistent, having no solutions.

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45:7+7-4:2-5:5*4+35:2 =? ( )