## Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips.Urn II contains three red chips and on

Question

Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips.Urn II contains three red chips and one white chip. You randomly select one chip from urn I and put itinto urn II. Then you randomly select a chip from urn II.What is the probability that the chip you select from urn II is red?

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2022-01-08T09:18:52+00:00
2022-01-08T09:18:52+00:00 1 Answer
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## Answers ( )

Answer:Step-by-step explanation:Step 1: Understanding the possible eventsSelecting a chip from Urn I and then adding that chip to Urn II and then selecting a red chip from Urn II can be completed in two ways:

A. Selecting a

red chip from Urn Iand adding it to Urn II and then selecting ared chip from Urn IIB. Selecting a

white chip from Urn Iand adding it to Urn II and then selecting ared chip from Urn IITherefore total probability is:Step 2: Probability of selecting either chip from Urn IUrn I contains 2 reds and 4 white chips, that gives a total of 6 chips.

Step 3: Probability of selecting a red chip from Urn IIUrn II originally contains 3 reds and 1 white chip, that gives a total of 4 chips.

Remember:Once a chip is added from Urn I to Urn II the total number of chips will increase in the Urn IICase 1:When a red chip is added from Urn I to Urn IIRed chips = 4

White chips = 1

Total Chips = 5

Case 2:When a white chip is added from Urn I to Urn IIRed chips = 3

White chips = 2

Total Chips = 5

Therefore the total Probability of selecting a chip from Urn I and then adding that chip to Urn II and then selecting a red chip from Urn II can be calculated as: