## Suppose you just received a shipment of eight televisions. Three of the televisions are defective. If two televisions are randomly​ selected

Question

Suppose you just received a shipment of eight televisions. Three of the televisions are defective. If two televisions are randomly​ selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not​ work?

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1 week 2021-09-15T20:14:49+00:00 1 Answer 0

1. Answer: The probability that both televisions work is The probability at least one of the two televisions does not​ work is .

Step-by-step explanation:

Given : Number of televisions received = 8

Number of defective televisions=3

Number of good television = 8-3=  5

Then , the number of ways to select any two television out of 8 = The number of ways to select two working televisions out of three = Now ,  If two televisions are randomly​ selected, the the probability that both televisions work Hence, the probability that both televisions work is Also , the probability at least one of the two televisions does not​ work = 1- P( both televisions work) Hence, the probability at least one of the two televisions does not​ work is 