systems of equations and inequalities solving systems by elimination {y= -x+1 {y= 4x-14 Question systems of equations and inequalities solving systems by elimination {y= -x+1 {y= 4x-14 in progress 0 Math 2 weeks 2021-09-08T13:32:37+00:00 2021-09-08T13:32:37+00:00 2 Answers 0

## Answers ( )

Answer:x = 3 , y = -2Step-by-step explanation:Solve the following system:

{y = 1 – x | (equation 1)

y = 4 x – 14 | (equation 2)

Express the system in standard form:

{x + y = 1 | (equation 1)

-(4 x) + y = -14 | (equation 2)

Swap equation 1 with equation 2:

{-(4 x) + y = -14 | (equation 1)

x + y = 1 | (equation 2)

Add 1/4 × (equation 1) to equation 2:

{-(4 x) + y = -14 | (equation 1)

0 x+(5 y)/4 = (-5)/2 | (equation 2)

Multiply equation 2 by 4/5:

{-(4 x) + y = -14 | (equation 1)

0 x+y = -2 | (equation 2)

Subtract equation 2 from equation 1:

{-(4 x)+0 y = -12 | (equation 1)

0 x+y = -2 | (equation 2)

Divide equation 1 by -4:

{x+0 y = 3 | (equation 1)

0 x+y = -2 | (equation 2)

Collect results:

Answer: {x = 3 , y = -2

Answer:## x = 3, y = -2 ⇒ (3, -2)

Step-by-step explanation: