Take a factor out of the square root: 48x^2 , where x≤0

Question

Take a factor out of the square root: 48x^2 , where x≤0

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3 months 2022-02-15T05:57:28+00:00 2 Answers 0 views 0

Answers ( )

1. Answer: $$4/x/\sqrt{3}$$

Step-by-step explanation:

$$\sqrt{48x^{2} }$$

this could also be written as :

$$\sqrt{48}$$ x $$\sqrt{x^{2}}$$

$$\sqrt{x^{2}}$$ = ±$$x$$ , so we have

$$\sqrt{48}/x/$$

$$\sqrt{48}$$ could be written as: $$\sqrt{16}$$ x $$\sqrt{3}$$

which will result into $$4\sqrt{3}$$

combining all together , we have

$$4/x/\sqrt{3}$$

Therefore , one of the factor of $$\sqrt{48x^{2} }$$ is $$4/x/\sqrt{3}$$

2. Question:

Which expression is equivalent to $$\sqrt{48x^{5} }$$ , if x > 0?

Answer:

$$4x^{2} \sqrt{3x}$$

Step-by-step explanation: