[tex]4(x – 1) {}^{2} – 9[/tex] ​

Question

[tex]4(x – 1) {}^{2} – 9[/tex]

in progress 0
Bella 3 months 2022-02-15T06:48:44+00:00 1 Answer 0 views 0

Answers ( )

    0
    2022-02-15T06:50:01+00:00

    Step-by-step explanation:

    (a-b)^2=(a^2-2*a*b+b^2)

    4*(x^2-2x+1)-9=4x^2-8x+4-9=4x^2-8x-5

    if you have to calculate the Δ

    there is it: 4x^2-8x-5=0

    Δ=b^2-4*a*c=64-4*4*(-5)=64+80=144

    [tex]x_{1,2}=[/tex]-b±Δ/2*a=8±12/8=

    [tex]x_{1}[/tex]=8+12/8=20/8|:4=5/2

    [tex]x_{2}[/tex]=8-12/8=-4/8|:4=-1/2

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )