-8x^2\sqrt{180} + 9x\sqrt{5x^2}

Question

-8x^2\sqrt{180} + 9x\sqrt{5x^2}

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Raelynn 1 week 2021-09-12T10:52:12+00:00 1 Answer 0

Answers ( )

    0
    2021-09-12T10:53:18+00:00

    Answer:

    -39x^{2} \sqrt{5}

    Step-by-step explanation:

    Firstly, you have to know these:

    a\sqrt{x} + b\sqrt{x} = (a+b)\sqrt{x} \\\sqrt{a.b^{2} } =b\sqrt{a} \\ c\sqrt{a.b^{2} } =(c.b)\sqrt{a} \\a\sqrt{x} - b\sqrt{x} = (a-b)\sqrt{x}

    About your question :

    \sqrt{180} = \sqrt{6^{2}.5} = 6\sqrt{5}

    -8x^{2} . 6\sqrt{5} = -48x^{2}\sqrt{5}

    \sqrt{5x^{2}} = x\sqrt{5}

    9x\sqrt{5x^{2}} = 9x.x\sqrt{5} = 9x^{2} \sqrt{5}

    -48x²√5 + 9x²√5  = -39√5

    Hope this helps ^-^

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45:7+7-4:2-5:5*4+35:2 =? ( )