Tennis balls are sold in cylindrical cans with the balls stacked one on top of the other. A tennis ball has a diameter of 6.7 cm. To the nea

Question

Tennis balls are sold in cylindrical cans with the balls stacked one on top of the other. A tennis ball has a diameter of 6.7 cm. To the nearest cubic centimeter, what is the minimum volume of the can that holds a stack of 4 tennis balls

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Allison 2 weeks 2022-01-08T05:33:42+00:00 1 Answer 0 views 0

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    2022-01-08T05:35:07+00:00

    Answer:

    629.92 cm^3

    Step-by-step explanation:

    The minimum volume of the can that can hold 4 tennis balls must have at least the same volume as 4 tennis balls.

    The volume of one tennis ball, V = \frac{4}{3}\pi  r^3

    where r = radius of the tennis ball

    The diameter of a ball = 6.7 cm

    Its radius will be = 6.7 / 2 = 3.35 cm

    Volume, V, will be:

    V = \frac{4}{3}\pi  (3.35)^3

    V = 157.48cm^3

    Hence, the volume of 4 balls will be:

    4 * V = 4 * 157.48 = 629.92 cm^3

    The minimum volume that the cylindrical can has to have is 629.92 cm^3.

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45:7+7-4:2-5:5*4+35:2 =? ( )