The amount of daily time that teenagers spend on a brand A cell phone is normally distributed with a given mean Mu = 2.5 hr and standard dev

Question

The amount of daily time that teenagers spend on a brand A cell phone is normally distributed with a given mean Mu = 2.5 hr and standard deviation Sigma = 0.6 hr. What percentage of the teenagers spend more than 3.1 hr? 5% 10% 16% 32%

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Melody 1 week 2021-09-08T03:31:59+00:00 2 Answers 0

Answers ( )

    0
    2021-09-08T03:33:01+00:00

    Answer:

    16

    Step-by-step explanation:

    right

    0
    2021-09-08T03:33:03+00:00

    Answer:

    Option 3./C. 16%

    Step-by-step explanation:

    First, we get the z-score by using the equation,

    Standard deviation Substituting,

    = 1

    Z-score = value – mean/

    Z-score = (3.1 – 2.5) / 0.6

    Converting the z-score to percentage will give us 0.841. Subtracting this value from 1.0 and multiplying The difference by 100%.

    Percentage = (1 – 0.0841) x 100%

    = 15.9% Thus, 15.9% of the teenagers spend more time In the cellphone.

    Didn’t you finally want to round it out,

    And you get 16%

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45:7+7-4:2-5:5*4+35:2 =? ( )