## The average (arithmetic mean) of the 43 numbers in list L is a positive number. The average of all 48 numbers in both lists L and M is 50 pe

Question

The average (arithmetic mean) of the 43 numbers in list L is a positive number. The average of all 48 numbers in both lists L and M is 50 percent greater than the average of the 43 numbers in list L. What percent greater than the average of the numbers in list L is the average of the numbers in list M?

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2 months 2021-09-26T21:48:43+00:00 1 Answer 0 views 0

Step-by-step explanation:

Given:

The average (arithmetic mean) of the 43 numbers in list L is a positive number.

The average of all 48 numbers in both lists L and M is 50 percent greater than the average of the 43 numbers in list L.

What percent greater than the average of the numbers in list L is the average of the numbers in list M?

Solution:

As the total number of observation in both list = 48

And the number of observation in list L = 43

Then, the number of observation in list M = 48 – 43 = 5

Let the average of the 43 numbers in list L = 100

Then the average of all 48 numbers in both lists L and M =

The average of the numbers in list M = 150 – 100 = 50

To find percent greater than the average of the numbers in list L in compare to average of the numbers in list M,

Average of the numbers in list L – average of the numbers in list M divided by the average of all 48 numbers in both lists L and M multiplied by 100

Thus, greater than the average of the numbers in list L is the average of the numbers in list M.