The base of a solid SSS is the region bounded by the ellipse 4x^2+9y^2=364x 2 +9y 2 =364, x, squared, plus, 9, y, squared, equals, 36. Cross

Question

The base of a solid SSS is the region bounded by the ellipse 4x^2+9y^2=364x 2 +9y 2 =364, x, squared, plus, 9, y, squared, equals, 36. Cross-sections perpendicular to the yyy-axis are equilateral triangles. Determine the exact volume of solid SSS.

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Genesis 3 weeks 2022-01-03T06:16:50+00:00 1 Answer 0 views 0

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    2022-01-03T06:18:04+00:00

    Answer:

    Step-by-step explanation:

    4x² + 9y² = 36

    Divide all  through by 9

    4/9x² + ²y² = 44

    \int\limits^3_0 {\pi y^{2} } \, dx

    \int\limits^3_0 {4-\frac{4}{9} }x^{2}  \, dx

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45:7+7-4:2-5:5*4+35:2 =? ( )