The circumference of the inner circle is 44 ft. The distance between the inner circle and the outer circle is 3 ft. By how many feet is the

Question

The circumference of the inner circle is 44 ft. The distance between the inner circle and the outer circle is 3 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner circle? Use 22/7 for pi

in progress 0
Amaya 2 weeks 2021-09-11T04:10:54+00:00 2 Answers 0

Answers ( )

    0
    2021-09-11T04:12:07+00:00

    Answer: 18.86 feet

    Step-by-step explanation:

    The formula for determining the circumference of a circle is expressed as

    Circumference = πD

    Where D represents the diameter of the circle.

    The circumference of the inner circle is 44 ft. It means that

    22/7 × D = 44

    22D = 7 × 44 = 308

    D = 308/22

    D = 14 ft

    The distance between the inner circle and the outer circle is 3 ft. This means that the diameter of the outer circle would be

    14 + 3 + 3 = 20 ft

    Circumference of the outer circle is

    22/7 × 20 = 62.86 ft

    The number of feet by which the circumference of outer circle is greater than the circumference of the inner circle is

    62.86 – 44 = 18.86 feet

    0
    2021-09-11T04:12:30+00:00

    Answer:

    18.9

    Step-by-step explanation:

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )