The data shows the total number of employee medical leave days taken for on-the-job accidents in the first six months of the year: 12, 6, 15

Question

The data shows the total number of employee medical leave days taken for on-the-job accidents in the first six months of the year: 12, 6, 15, 9, 18, 12. Use the data for the Exercise. Find the sum of squares of the deviations from the mean.

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Amaya 1 week 2021-11-22T09:55:25+00:00 1 Answer 0 views 0

Answers ( )

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    2021-11-22T09:56:42+00:00

    Answer:

    90

    Step-by-step explanation:

    The sum of squares of the deviation from mean=sum(x-xbar)²=?

    x

    12

    6

    15

    9

    18

    12

    xbar=sumx/n

    xbar=(12+6+15+9+18+12)/6=72/6=12

    x      x-xbar       (x-xbar)²

    12      12-12=0     0

    6       6-12=-6     36

    15      15-12=3      9

    9       9-12=-3       9

    18      18-12=6      36

    12      12-12=0      0

    sum(x-xbar)²=0+36+9+9+36+0=90

    So, the sum of squares of the deviations from the mean is 90.

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45:7+7-4:2-5:5*4+35:2 =? ( )