The height of an object t seconds after it is thrown from a height of h feet is modelled by the equation h(t) = -16t^2 + vt + h. If the bal

Question

The height of an object t seconds after it is thrown from a height of h feet is modelled by the equation h(t) = -16t^2 + vt + h. If the ball is thrown from a point 6 feet above ground with an initial velocity, v, of 30 feet per second, how long will it take for the ball to hit the ground???‚Äč

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Josephine 1 week 2021-09-11T22:54:31+00:00 1 Answer 0

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    2021-09-11T22:55:34+00:00

    Answer:

    At 0.713 second the ball will hit the ground

    Step-by-step explanation:

    The height of an object t seconds after it is thrown from a height of h feet is modeled by the equation:

    h(t) = -16t^2 + vt + h

    The ball is thrown from a point 6 feet above ground with an initial velocity, v, of 30 feet per second, equation becomes:

    h(t) = -16t^2 + 3t + 6

    It is required to find the time when the ball hits the ground. At that point, h(t) =0.

    So,

    -16t^2 + 3t + 6=0

    Above is a quadratic equation, the value of time is given by :

    t = -0.526 s and t = 0.713 seconds

    So, at 0.713 second the ball will hit the ground.

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