## The largest taco contained approximately 1 kg of onion for every 6.8 kg grilled steak. The total weight of these two ingredients was 617.6 k

Question

The largest taco contained approximately 1 kg of onion for every 6.8 kg grilled steak. The total weight of these two ingredients was 617.6 kg. How many kilograms of each ingredient were used?

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3 weeks 2021-09-25T06:28:11+00:00 2 Answers 0

Step-by-step explanation:

For a taco:

Ingredient:

1 kg of onion for every 6.8 kg grilled steak

Wt = 617.6 kg

Let x = mass of onion and y = mass of grilled steak

x + 6.8y = 617.6

Can also be written as:

x + 6.8x = 617.6

x = 617.6/7.8

= 79.2.

2. Answer: Onion = 79.17 kg

Grilled steak = 538.356 kg

Step-by-step explanation:

Hi, to answer this question we have to write an equation with the information given:

1 k + 6.8 k = 617.6

Where “k” is a constant value, a multiplier.

Solving for k:

7.8 k = 617.6

k = 617.6 /7.8

k= 79.17

So:

Amount of onion used:

1 (79.17) = 79.17 kg

Amount of grilled steak used:

6.8 (79.17) = 538.356 kg

Feel free to ask for more if needed or if you did not understand something.