The largest taco contained approximately 1 kg of onion for every 6.8 kg grilled steak. The total weight of these two ingredients was 617.6 k

Question

The largest taco contained approximately 1 kg of onion for every 6.8 kg grilled steak. The total weight of these two ingredients was 617.6 kg. How many kilograms of each ingredient were used?

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Abigail 3 weeks 2021-09-25T06:28:11+00:00 2 Answers 0

Answers ( )

    0
    2021-09-25T06:29:33+00:00

    Answer:

    Step-by-step explanation:

    For a taco:

    Ingredient:

    1 kg of onion for every 6.8 kg grilled steak

    Wt = 617.6 kg

    Let x = mass of onion and y = mass of grilled steak

    x + 6.8y = 617.6

    Can also be written as:

    x + 6.8x = 617.6

    x = 617.6/7.8

    = 79.2.

    0
    2021-09-25T06:29:51+00:00

    Answer: Onion = 79.17 kg

    Grilled steak = 538.356 kg

    Step-by-step explanation:

    Hi, to answer this question we have to write an equation with the information given:

    1 k + 6.8 k = 617.6  

    Where “k” is a constant value, a multiplier.

    Solving for k:

    7.8 k = 617.6

    k = 617.6 /7.8  

    k= 79.17

    So:

    Amount of onion used:

    1 (79.17) = 79.17 kg

    Amount of grilled steak used:

    6.8 (79.17) = 538.356 kg

    Feel free to ask for more if needed or if you did not understand something.

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