The length of a rectangle is 5 inches more than the width. The area is 33 square inches. Find the length and width . Round to the nearest te

Question

The length of a rectangle is 5 inches more than the width. The area is 33 square inches. Find the length and width . Round to the nearest tenth if necessary.

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Charlie 1 hour 2021-10-12T23:32:14+00:00 1 Answer 0

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    2021-10-12T23:33:37+00:00

    Answer:

    the length and width . Round to the nearest tenth are 8.8 inches and 3.8 inches respectively.

    Step-by-step explanation:

    The area A of a rectangle is the product of the length L and width W. This may be expressed mathematically as

    A = L * W

    As such, given that the length is 5 inches more than the width,

    L = W + 5

    33 = W(W + 5)

    W² + 5W  – 33 = 0

    Using the formula method which states that

    s = -b±√(b²-4ac)/2a

    W = -5 ± √5² – 4(1)(-33)/2

    = -5 ± 12.53/2

    = 7.53/2 (since length cannot be negative)

    = 3.755 inches

    L = 3.755 + 5

    = 8.755 inches

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45:7+7-4:2-5:5*4+35:2 =? ( )