The length of a rectangular piece of steel is 4 meters less than double the width. The perimeter of the steel is 22 meters find the length a

Question

The length of a rectangular piece of steel is 4 meters less than double the width. The perimeter of the steel is 22 meters find the length and width of steel

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Valentina 1 week 2021-09-13T04:57:46+00:00 2 Answers 0

Answers ( )

    0
    2021-09-13T04:58:49+00:00

    Answer: length = 6 meters

    Width = 5 meters

    Step-by-step explanation:

    Let L represent the length of the rectangular piece of steel.

    Let W represent the width of the rectangular piece of steel.

    The formula for determining the perimeter of a rectangle is expressed as

    Perimeter = 2(L + W)

    The perimeter of the steel is 22 meters. This means that

    2(L + W) = 22

    Dividing through by 2, it becomes

    L + W = 11 – – – – – – – – – – – -1

    The length of a rectangular piece of steel is 4 meters less than double the width. This means that

    L = 2W – 4

    Substituting L = 2W – 4 into equation 1, it becomes

    2W – 4 + W = 11

    2W + W = 11 + 4

    3W = 15

    W = 15/3

    W = 5

    L = 2W – 4 = 2 × 5 – 4

    L = 10 – 4

    L = 6

    0
    2021-09-13T04:59:01+00:00

    Answer:

    Length= 6 m         \\ Width = 5m

    Step-by-step explanation:

    Let the width of the piece be ‘W

    Length of the piece be ‘L

    According to the given statement

                    Length=2W-4

    Perimeter = 22 m

    Perimeter of the rectangular sheet=

                                     2(L+W)\\                   22= 2(2W-4+W)\\             22=2(3W-4)\\               11=3W-4\\                 3W=11+4\\                 3W=15\\                     W= 5\\

       Length=2W-4

                    =2(5)-4\\=10-4\\Length=6 m

       Length= 6 m         \\ Width = 5m

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