## The Maclaurin series for sin−1(x) is given by sin−1(x) = x + [infinity] n = 1 1 · 3 · 5 (2n − 1) 2 · 4 · 6 (2n) x2n+1 2n + 1 . Use the first

Question

The Maclaurin series for sin−1(x) is given by sin−1(x) = x + [infinity] n = 1 1 · 3 · 5 (2n − 1) 2 · 4 · 6 (2n) x2n+1 2n + 1 . Use the first five terms of the Maclaurin series above to approximate sin−1 3 7 . (Round your answer to eight decimal places.)

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2021-10-18T07:03:43+00:00
2021-10-18T07:03:43+00:00 1 Answer
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## Answers ( )

Answer:0.44290869

Step-by-step explanation:The Maclaurin series for sin⁻¹(x) is given by

sin⁻¹(x) = x +

Use the first five terms of the Maclaurin series above to approximate sin⁻¹ . (Round your answer to eight decimal places.)

Answer

sin⁻¹(x) = x +

in the above equation summation from n=1 to ∞

we are estimating this for the first 5 terms as follows

sin⁻¹(x) = x + + + +

sin⁻¹(x) = x + + + +

now to get

sin⁻¹() substitute

hence,

sin⁻¹() =

sin⁻¹() = 0.42857142 + 0.01311953 + 0.00108437 + 0.00011855 + 0.00001482

= 0.44290869