The management of Priority Health Club claims that its members lose an average of 10 pounds or more within the first month after joining the

Question

The management of Priority Health Club claims that its members lose an average of 10 pounds or more within the first month after joining the club. A consumer agency that wanted to check this claim took a random sample of 36 club members of this health club and found that they lost an average of 10.8 pounds within the first month of membership. The population standard deviation is known to be 2.4 pounds. Test at the .05 level ________.

in progress 0
Clara 2 weeks 2021-09-07T20:22:10+00:00 1 Answer 0

Answers ( )

    0
    2021-09-07T20:24:07+00:00

    Answer:

    z=\frac{10.8-10}{\frac{2.4}{\sqrt{36}}}=2    

    Now we can calculate the p value since we are using ta right tailed test

    p_v =P(z>2)=0.0228

    Since the p value is lower than the significance level provided of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the members of the Priority Health Club lose an average of 10 pounds or more within the first month after joining the club

    Step-by-step explanation:

    Data provided

    \bar X=10.8 represent the sample eman for the amount of weigth lost

    \sigma = 2.4 represent the population standard deviation

    n=36 sample size    

    \mu_o =10 represent the value to test

    \alpha=0.05 represent the significance level for the hypothesis test.  

    z would represent the statistic

    p_v represent the p value for the test

    Hypothesis to test

    We want to determine if the members of the Priority Health Club lose an average of 10 pounds or more within the first month after joining the club , the system of hypothesis would be:    

    Null hypothesis:\mu \leq 10    

    Alternative hypothesis:\mu > 10    

    Since we know the population deviation the statistic can be founded like this:

    z=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

    Replacing theinfo given we got:

    z=\frac{10.8-10}{\frac{2.4}{\sqrt{36}}}=2    

    Now we can calculate the p value since we are using ta right tailed test

    p_v =P(z>2)=0.0228

    Since the p value is lower than the significance level provided of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the members of the Priority Health Club lose an average of 10 pounds or more within the first month after joining the club

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )