## The owner of the Rancho Grande has 2,980 yd of fencing with which to enclose a rectangular piece of grazing land situated along the straight

Question

The owner of the Rancho Grande has 2,980 yd of fencing with which to enclose a rectangular piece of grazing land situated along the straight portion of a river. If fencing is not required along the river, what are the dimensions (in yd) of the largest area he can enclose?

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1 week 2021-09-12T23:08:37+00:00 1 Answer 0

rectangle with maximum area has dimensions of 745 yd x 1490 yd

Step-by-step explanation:

the rectangular area is

Area = x*y , where x= side along the river , y = side perpendicular to the river

since we have only 2980 yd of fencing, the total fencing ( perimeter) will be

x+2*y = 2980 yd =a

then solving for x

x= a – 2*y

replacing in the area expression

A=Area = x*y = (a- 2*y) *y = a*y – 2*y²

the maximum area is found when the derivative with respect to y is 0 , then

dA/dy= a – 4*y = 0 → y=a/4 = 2980 yd /4 = 745 yd

then

x= a – 2*y = a – 2* a/4 = a/2 = 2980 yd /2 = 1490 yd

then the rectangle with maximum area has dimensions of 745 yd x 1490 yd