The perimeter of a rectangle is 60 m, and it’s length is twice it’s width. Find the length of the rectangle.

Question

The perimeter of a rectangle is 60 m, and it’s length is twice it’s width. Find the length of the rectangle.

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Remi 2 weeks 2021-09-28T19:25:27+00:00 2 Answers 0

Answers ( )

    0
    2021-09-28T19:26:39+00:00

    Answer:

    therefore, the width of the rectangle is 10m and length is 20m.

    Step-by-step explanation:

    Let n represent width

    Let n represent width #2

    let 2n represent length

    let 2n represent length #2

    n+n+2n+2n=60

    6n=60

    n=60/6

    n=10

    width=10

    length= 2n

    = 2*10

    =20

    0
    2021-09-28T19:27:21+00:00

    Let x represent the width of the rectangle.
    We know 2x=length
    Perimeter of a rectangle is 2(length)+2(width)
    So we can make an equation for the perimeter of this particular rectangle.
    2(2x)+2(x)=60
    4x+2x=60
    6x=60
    x=10.
    Since the width is equal to x, we know that the width of this rectangle is 10 m.
    And, the length is twice of the width.
    10*2=20
    Therefore, the length of the rectangle is 20 meters.

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