the perimeter of rectangle is 44 inches.if the length of the rectangle is 7 more than half its width.what is the area of the rectangle . PLS

Question

the perimeter of rectangle is 44 inches.if the length of the rectangle is 7 more than half its width.what is the area of the rectangle . PLSS HELP

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Amara 4 days 2021-10-10T06:23:19+00:00 2 Answers 0

Answers ( )

    0
    2021-10-10T06:25:12+00:00

    Answer:

    120 sq. in

    Step-by-step explanation:

    perimeter = 44 inches

    length is half the width + 7

    a = length

    b = width

    a + a + b + b = 44

    a + b = 22

    a + b/2 = 7

    b + b/2 + 7 = 22

    b + b/2 = 15

    2b + b = 30

    a = 12

    b= 10

    area = a x b

    area = 120 square inches

    0
    2021-10-10T06:25:16+00:00

    Answer:

    The area of the rectangle is 120 inches squared.

    Step-by-step explanation:

    First, identify what you know:

    1) The perimeter of the rectangle is 44 inches.

    2) The length of the rectangle is 7 more than half its width.

    To solve the area of this rectangle, we need to know the width and length of the shape. First, it’s important that we know the formula for finding the perimeter, and the area of a rectangle.

    Perimeter = 2 x (L + W)

    Area = L x W

    Now, we can create a formula to demonstrate our problem

    Perimeter (44 inches) = 2 (W + ((1/2 x W) + 7)))

    Now, we can divide both sides in half, to simplify.

    22 inches = (W + ((1/2 x w) + 7))

    If you input the values 12, and 10, you’ll see that it works!

    22 inches = (10 + ((1/2 x 10) + 7))

    22 inches = (10 + (5 + 7))

    22 inches = (10 + 12)

    122 inches = 22 inches

    Now, using the Area formula, we can solve for the area of the rectangle, since we know the length and the width.

    A = L x W

    A = 12 X 10

    A = 120 inches squared.

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45:7+7-4:2-5:5*4+35:2 =? ( )