The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability distribution:

Question

The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability distribution: x 0 1 2 3 4 5 P(X = x) 0.20 0.30 0.20 0.15 0.10 0.05 On average, how many accidents are there in the intersection in a week? a. 5.3 b. 2.5 c. 1.8 d. 0.30 e. 0.1667

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Audrey 1 month 2021-10-20T07:08:17+00:00 1 Answer 0 views 0

Answers ( )

  1. Ava
    0
    2021-10-20T07:10:00+00:00

    Answer:

    The average accidents in the intersection per week is 1.8                

    Step-by-step explanation:

    We are given the following in he question:

    x:                0        1          2        3        4       5

    P(X = x):  0.20   0.30   0.20   0.15   0.10   0.05

    We have to find the number of average accidents per week.

    Formula:

    E(x) = \displaystyle\sum x_iP(x_1)\\E(x)=0(0.20)+ 1(0.30)+ 2(0.20)+ 3(0.15)+ 4(0.10) + 5(0.05)\\E(x) = 1.8

    Thus, the average accidents in the intersection per week is 1.8

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45:7+7-4:2-5:5*4+35:2 =? ( )