the singh and robinson families planned a trip to busch gardens. they needed to buy one ticket per person and then pay for parking. the sing

Question

the singh and robinson families planned a trip to busch gardens. they needed to buy one ticket per person and then pay for parking. the singh’s spent $335 for 5 people and the robinsons spent $ 465 for 7 people. how much did each ticket cost? How much was parking

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Camila 2 weeks 2021-09-07T22:10:20+00:00 1 Answer 0

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    2021-09-07T22:12:16+00:00

    Let x represent cost of each ticket and y represent cost of parking.

    We have been given that the Singh’s spent $335 for 5 people and parking. We can represent this information in an equation as:

    5x+y=335...(1)

    We are also told that the Robinson spent $465 for 7 people and parking. We can represent this information in an equation as:

    7x+y=465...(2)

    Now we will use elimination method to solve our given system of equations.

    Upon subtracting equation (1) from equation (2), we will get:

    7x-5x+y-y=465-335

    2x=130

    \frac{2x}{2}=\frac{130}{2}

    x=65

    Therefore, the each ticket costs $65.

    Upon substituting x=65 in equation (1), we will get:

    5(65)+y=335

    325+y=335

    325-325+y=335-325

    y=10

    Therefore, the parking costs $10.

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