The slant asymptote of f(x)=x^2+3x-4/x is y=3x+1 Please select the best answer from the choices provided T F

Question

The slant asymptote of f(x)=x^2+3x-4/x is y=3x+1

Please select the best answer from the choices provided

T
F

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Kaylee 3 weeks 2021-10-03T22:07:46+00:00 1 Answer 0

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    2021-10-03T22:09:35+00:00

    Answer:  False

    Step-by-step explanation:

    y=\dfrac{x^2+3x-4}{x}\quad =\quad x+3-\dfrac{4}{x}

    So, the slant asymptote is: y = x + 3

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