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The sum of the ages of 3 members of a family is 86 years. George has half age of Sofia and Katerina is 14 years younger than Sofia. Find the

Home/Math/The sum of the ages of 3 members of a family is 86 years. George has half age of Sofia and Katerina is 14 years younger than Sofia. Find the

The sum of the ages of 3 members of a family is 86 years. George has half age of Sofia and Katerina is 14 years younger than Sofia. Find the

Question

The sum of the ages of 3 members of a family is 86 years. George has half age of Sofia and Katerina is 14 years younger than Sofia. Find their ages! plz help me

## Answers ( )

Answer:K: 26

G: 20

S: 40

Step-by-step explanation:let sofia’s age be 2x (easier to divide),

george’s age is x (half)

katerina’s age is 2x – 14

so add them all up and you get:

5x – 14 = 86

5x = 100

x = 20 (george’s age)

so sofia is

2(20)

= 40 years old

and katerina is

40 – 14

= 26 years old

*hope this helps :^)

Answer:George – 20, Sofia – 40, Katerina – 26

Step-by-step explanation:G=x, S=2x, K=2x-14

x+2x+2x-14=86

5x=100

x=20

George=20, Sofia=2×20=40, Katerina=2×20-14=26