The sum of the squares of two positive integers is 106 and the difference of the squares of the numbers is 56. Find the numbers. Group

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The sum of the squares of two positive integers is 106 and the difference of the squares of the numbers is 56. Find the numbers.
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Mackenzie 2 months 2021-09-23T20:34:07+00:00 1 Answer 0 views 0

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    2021-09-23T20:35:21+00:00

    Answer:

    x=56, y=52.7358

    Step-by-step explanation:

    x + y = 106

    x = 106 – y

    x^2 – y^2 = 56

    (106 – y)^2 – y^2 = 56

    11236 – 212y + y^2 – y^2 = 56

    11236 – 212y = 56

    212y = 11236 – 56

    212y = 11180

    y = 52.7358

    x = 106 – y = 106 – 52.7358 = 53.2642

    (53.2642)^2 – (52.7358)^2 = 2837.08 – 2781.08 = 56

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45:7+7-4:2-5:5*4+35:2 =? ( )