## The sum of the squares of two positive integers is 106 and the difference of the squares of the numbers is 56. Find the numbers. Group

Question

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## Answers ( )

Answer:x=56, y=52.7358

Step-by-step explanation:x + y = 106

x = 106 – y

x^2 – y^2 = 56

(106 – y)^2 – y^2 = 56

11236 – 212y + y^2 – y^2 = 56

11236 – 212y = 56

212y = 11236 – 56

212y = 11180

y = 52.7358

x = 106 – y = 106 – 52.7358 = 53.2642

(53.2642)^2 – (52.7358)^2 = 2837.08 – 2781.08 = 56