The sum of three consecutive numbers is 72. What is the smallest of these numbers? x + (x + 1) + (x + 2) = 72 x+ (x

Question

The sum of three consecutive numbers is 72. What is the smallest of
these numbers?

x + (x + 1) + (x + 2) = 72
x+ (x + 2) + (x + 4) = 72
3x = 72
x + y + z =72

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Madelyn 2 months 2021-10-14T04:12:12+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-10-14T04:14:00+00:00

    Answer:

    The smallest number is 23

    Step-by-step explanation:

    Let x be the first number

    x+1 is the next consecutive number

    x+2 is the next consecutive number

    The sum is

    x+ x+1 + x+2 = 72

    Combine like terms

    3x+3 = 72

    subtract 3 from each side

    3x+3-3 = 72-3

    3x = 69

    Divide each side by 3

    3x/3 = 69/3

    x = 23

    x+1 = 24

    x+2 =25

    The numbers are

    23,24,25

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