The table below shows the lengths and weights of six dolphins at an aquarium. Use the data from Pax and Snowflake to create a linear m

Question

The table below shows the lengths and weights of six dolphins at an aquarium. Use the data from Pax and Snowflake to
create a linear model that predicts the weight (y) of a dolphin given its length (X). Which dolphin’s weight differs most from th
value predicted by this model?
Name
Snowflake
Shadow
Corky
Pax
JoJo
Blaze
Length (ft)
8.2
74
8.4
7.6
5.8
6.8
Weight (lb)
549
501
557
519
460
488
Blaze
JOJO
Corky
Shadow

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Adeline 2 weeks 2022-01-03T12:36:00+00:00 2 Answers 0 views 0

Answers ( )

    0
    2022-01-03T12:37:32+00:00

    Answer:

    jojo on edge

    Step-by-step explanation:

    0
    2022-01-03T12:37:50+00:00

    Answer:

    The dolphin’s weight that differs most from the value predicted by this model is JoJo’s (31 lb of difference)

    Step-by-step explanation:

    Name                 Length (ft)           Weight (lb)

    Snowflake             8.2                        549

    Shadow                7.4                         501

    Corky                    8.4                         557

    Pax                        7.6                         519

    JoJo                      5.8                         460

    Blaze                    6.8                         488

    Use the data from Pax and Snowflake to  create a linear model that predicts the weight (y) of a dolphin given its length (X). Which dolphin’s weight differs most from the value predicted by this model?

    Let’s elaborate the model this way:

    Snowflake’s length – Pax’s length = 8.2 – 7.6 = 0.6 ft

    Snowflake’s weight – Pax’s weight = 549 – 519 = 30 lb

    Ratio = 30/0.6 = 50 lb/ft

    This means that for every foot of length, the dolphin has a variable weight of 50 lb. However, if we multiply the ratio by the actual length of the two dolphins, we will have these results:

    Snowflake = 50 * 8.2 = 410

    Pax = 50 * 7.6 = 380

    What is the common difference in both cases?

    Snowflake = Actual weight – Ratio * Length = 549 – 410 = 139

    Pax = Actual weight – Ratio * Length = 519 – 380 = 139

    The common difference is 139. Therefore, the linear model that predicts the weight (y) of a dolphin given its length (X) is:

    y = 139 + 50x

    Now, let’s use the linear equation or model to calculate the weight of the remaining four dolphins, as follows:

    Blaze  y = 139 + 50 * 6.8 = 479 ⇒ difference of 9 lb (488 – 479)

    JoJo   y = 139 + 50 * 5.8 = 429 ⇒ difference of 31 lb (460 – 429)

    Corky   y = 139 + 50 * 8.4 = 559 ⇒ difference of 2 lb  (559 – 557)

    Shadow  y = 139 + 50 * 7.4 = 509 ⇒ difference of 8 lb  (509 – 501)

    The dolphin’s weight that differs most from the value predicted by this model is JoJo’s (31 lb of difference)

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