The vertices of AABC are A(-6, -7), B(-3,-10) and C(-5,2). Find the vertices of AA’B’C’. given the translation rule below.

Question

The vertices of AABC are A(-6, -7), B(-3,-10) and
C(-5,2). Find the vertices of AA’B’C’. given the
translation rule below.
(x, y) (x – 2. y – 7)
a A (-8, -14), B (-5, -17), C'(-7,-5)
b
A'(-6, -12), B’ (-6, -18).C'(-9, -12)
C A'(-12, -16), B(-10, -17), C'(-6, -5)
d
A'(-9, -20), B'(-6, -12). C'(-8, 8)

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Arianna 2 weeks 2021-09-09T11:22:39+00:00 1 Answer 0

Answers ( )

    0
    2021-09-09T11:24:15+00:00

    Answer:

    A, but try the rest of the points!

    Step-by-step explanation:

    I assume AABC means triangle ABC

    Just do the operation to each point.  so A is (-6, -7)  (x – 2. y – 7) is telling you subtract 2 from -6 and 7 from -7 or in other words it changes from  (-6, -7)  to (-6 – 2. -7 – 7) = (-8, -14)

    Only one answer has that point for A’, but you should really really really try the rest.

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45:7+7-4:2-5:5*4+35:2 =? ( )