Then, the bug ran from −100 to 100. What distance did it cover? If the average speed of the bug during this run was 20 units per minute, how

Question

Then, the bug ran from −100 to 100. What distance did it cover? If the average speed of the bug during this run was 20 units per minute, how long did this run take?

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Eloise 2 weeks 2021-09-08T17:23:10+00:00 1 Answer 0

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    2021-09-08T17:24:59+00:00

    Answer:

    200 units.

    10 minutes.

    Step-by-step explanation:

    Distance = 100 – (-100)

    = 100 + 100

    = 200 units.

    Speed = distance / time

    20 = 200/ t

    t =  200/20

    = 10 minutes.

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45:7+7-4:2-5:5*4+35:2 =? ( )