## There are seven competitors in the jured art showcase in how many ways may the judges choose a winner and a fost runner-up)

Question

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## Answers ( )

The number of ways in which the judge can choose the winner and a first runner up = 42Step-by-step explanation:Step 1 :Number of competitors in the art show case = 7

We need to

find the number of ways the judges can choose the winner and the first runner up.Step 2 :The number of ways using which the judge can choose the winner = 7

(Since there are 7 competitors)

The number of ways using which the judge can choose the first runner up = 6

(

Sincethe winner is already chosen, the remaining number of competitors will be 7 – 1 =6)Hence the number of ways in which the judge can choose the winner and a first runner up = 7 × 6 = 42

Step 3 :Answer :The number of ways in which the judge can choose the winner and a first runner up = 42