There are seven competitors in the jured art showcase in how many ways may the judges choose a winner and a fost runner-up)

Question

There are seven competitors in the jured art showcase in how many ways may the judges choose a winner
and a fost runner-up)

in progress 0
Savannah 2 weeks 2021-09-08T19:09:13+00:00 1 Answer 0

Answers ( )

    0
    2021-09-08T19:10:35+00:00

    The number of ways in which the judge can choose the  winner  and a first runner up = 42

    Step-by-step explanation:

    Step 1 :

    Number of competitors in the art show case = 7

    We need to find the number of ways the judges can choose the winner and the first runner up.

    Step 2 :

    The number of ways using which the judge can choose the winner = 7

    (Since there are 7 competitors)

    The number of ways using which the judge can choose the first runner up = 6

    (Since the winner is already chosen, the remaining number of competitors will be 7 – 1 =6)

    Hence the number of ways in which the judge can choose the  winner  and a first runner up = 7 × 6 = 42

    Step 3 :

    Answer :

    The number of ways in which the judge can choose the  winner  and a first runner up = 42

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )